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2x^2=55^2
We move all terms to the left:
2x^2-(55^2)=0
We add all the numbers together, and all the variables
2x^2-3025=0
a = 2; b = 0; c = -3025;
Δ = b2-4ac
Δ = 02-4·2·(-3025)
Δ = 24200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24200}=\sqrt{12100*2}=\sqrt{12100}*\sqrt{2}=110\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110\sqrt{2}}{2*2}=\frac{0-110\sqrt{2}}{4} =-\frac{110\sqrt{2}}{4} =-\frac{55\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110\sqrt{2}}{2*2}=\frac{0+110\sqrt{2}}{4} =\frac{110\sqrt{2}}{4} =\frac{55\sqrt{2}}{2} $
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